220=-16t^2-22

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Solution for 220=-16t^2-22 equation: 



220=-16t^2-22

We move all terms to the left:

220-(-16t^2-22)=0

We get rid of parentheses

16t^2+22+220=0

We add all the numbers together, and all the variables

16t^2+242=0

a = 16; b = 0; c = +242;
Δ = b2-4ac
Δ = 02-4·16·242
Δ = -15488
Delta is less than zero, so there is no solution for the equation

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